Even/Odd properties of integer algebraic expressions
Question
Three of the five positive integers p, q, r, s, t are even and two of them are odd (not necessarily in order). Consider the following:
Which of the above statements is/are correct?
Options
1 only
2 only
Both 1 and 2
Neither 1 nor 2
Explanation
Analyze each parity expression based on the fixed inventory of three even (E) and two odd (O) integers[cite: 3105, 3106]:
Statement 1: p + q + r - s - t. In algebra, parity is invariant under addition and subtraction (i.e., A - B has the same parity as A + B). Therefore, the expression simplifies to the sum of all five numbers: p + q + r + s + t. Sum = E + E + E + O + O = Even + Even = Even. Thus, it is definitely even. Statement 1 is correct.
Statement 2: 2p + q + 2r - 2s + t. Any term multiplied by 2 becomes strictly even regardless of its origin (2p, 2r, 2s \rightarrow E). The expression collapses to: Even + q + Even - Even + t = Even + (q + t). Since q and t are part of the original five-integer pool, let's look at the worst cases for the leftover elements (q, t):
Since the result depends on which specific variables hold the odd values, it is not definitely odd.
Self-Correction on Statement 2 analysis: Let's re-verify if the question parameters restrict the allocation. If q and t can be either even or odd depending on the permutation, then it is not definitely odd. Thus, only Statement 1 holds with absolute certainty.
Answer: (a).
Question details
Year
2023
Paper
CSAT
Question
Q14
Section
Numerical Ability
Sub-topic
Number Properties
Type
Number theory
Difficulty
Medium
Source hint
Number theory
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