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Q30·CSAT · Prelims 2025

Successive percentage increase-decrease relation

NumericalPercentagesAlgebra & equationsHard

Question

The price (p) of a commodity is first increased by k%; then decreased by k%; again increased by k%; and again decreased by k%. If the new price is q, then what is the relation between p and q?

Options

a

p(10^4 - k^2)^2 = q × 10^8

Answer
b

p(10^4 - k^2)^2 = q × 10^4

c

p(10^4 - k^2) = q × 10^4

d

p(10^4 - k^2) = q × 10^8

Explanation

Applying successive percentage changes, the final price q is expressed as: q = p × (1 + k/100) × (1 - k/100) × (1 + k/100) × (1 - k/100) Using the algebraic identity (a+b)(a-b) = a² - b², we group the pairs: q = p × (1 - k²/10000) × (1 - k²/10000) ⟨MATH⟩q = p × \left(10000 - k²/10000\right)²⟨/MATH⟩ q = p × (10^4 - k²)²/(10^4)² q = p × (10^4 - k²)²/10^8 Cross-multiplying yields: q × 10^8 = p(10^4 - k²)².

For any sequence of +k\% and -k\% changes, pair them up to immediately apply the net change multiplier of (1 - k²/100²).

Answer: (a).

Question details

Year

2025

Paper

CSAT

Question

Q30

Section

Numerical Ability

Sub-topic

Percentages

Type

Algebra & equations

Difficulty

Hard

Source hint

Percentage algebra

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