Comparative - average vs product of 11 numbers
Question
Consider a set of 11 numbers: Value-I = Minimum value of the average of the numbers of the set when they are consecutive integers ≥ -5. Value-II = Minimum value of the product of the numbers of the set when they are consecutive non-negative integers. Which one of the following is correct?
Options
Value-I < Value-II
Value-II < Value-I
Value-I = Value-II
Cannot be determined due to insufficient data
Explanation
Evaluate each value independently. Value-I asks for the minimum average of 11 consecutive integers \ge -5. The lowest possible set is \{-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5\}. The average of an arithmetic progression is its middle term. The middle term is 0. So Value-I = 0. Value-II asks for the minimum product of 11 consecutive non-negative integers. The smallest such set starts at 0: \{0, 1, ..., 10\}. Any product containing zero is 0. So Value-II = 0.
Answer: (c).
Question details
Year
2025
Paper
CSAT
Question
Q57
Section
Data Interpretation & Sufficiency
Sub-topic
Comparative Quantitative
Type
Comparative quantitative
Difficulty
Hard
Source hint
Quantitative comparison
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