Quantitative Aptitude — Exponential Bounds

We need to find the number of integer values of n such that 2^n yields a three-digit number (100 \le 2^n \le 999).

Let us calculate the relevant sequential powers of 2 directly:

Let us count the distinct values. Wait, let's re-verify if any value was missed. Let's look closer at the options list: (a) 1, (b) 2, (c) 3, (d) 4[cite: 3929, 3930, 3931, 3932]. The distinct powers matching the three-digit range are 2^7, 2^8, and 2^9, which gives exactly 3 valid numbers. Let us confirm the question parameters and option alignment. Under standard key groupings, the total count maps to 3 valid entries.

Answer: (c).