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Q28·CSAT · Prelims 2026

Logic — Standard Syllogisms

ReasoningSyllogism — All/SomeSyllogism● Easy

Question

Consider the following statements: Every red is blue. Every blue is green. Every green is yellow. Which of the following statements denoted by P, Q and R are correct? P. Every blue is yellow. Q. Every red is green. R. Every red is yellow. Select the answer using the code given below.

Options

a

P and Q only

b

Q and R only

c

P and R only

d

P, Q and R

Answer

Explanation

Let us translate the absolute universal premises ('Every' means 'All') into standard set inclusion relationships:

1Red \subseteq Blue
2Blue \subseteq Green
3Green \subseteq Yellow

This creates a nested chain of sets: Red \subseteq Blue \subseteq Green \subseteq Yellow.

Evaluate P: 'Every blue is yellow' translates to Blue \subseteq Yellow[cite: 4032, 4033]. Since Blue \subseteq Green and Green \subseteq Yellow, this is correct via transitivity .
Evaluate Q: 'Every red is green' translates to Red \subseteq Green[cite: 4032, 4034]. Since Red \subseteq Blue and Blue \subseteq Green, this is correct .
Evaluate R: 'Every red is yellow' translates to Red \subseteq Yellow[cite: 4032, 4034]. Since Red is the innermost set and Yellow is the outermost set, this inclusion is correct.

Since all three statements are logically correct, option (d) is the correct choice.

Universal positive propositions ('Every' or 'All') follow standard transitive nesting logic, meaning inner subsets are automatically included within all outer categories.

Answer: (d).

Question details

Year

2026

Paper

CSAT

Question

Q28

Section

Logical Reasoning

Sub-topic

Syllogism — All/Some

Type

Syllogism

Difficulty

Easy

Source hint

Syllogisms — intersecting set inclusions

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