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Q27·CSAT · Prelims 2022

Fundamental principle of counting for path combinations

NumericalPermutations & CombinationsFactual singleEasy

Question

A, B and C are three places such that there are three different roads from A to B, four different roads from B to C and three different roads from A to C. In how many different ways can one travel from A to C using these roads?

Options

a

10

b

13

c

15

Answer
d

36

Explanation

There are two completely independent primary routes to travel from A to C: an indirect route via B, and a direct route.

Route 1 (Indirect via B): Travel A to B (3 options) AND travel B to C (4 options). Combinations = 3 × 4 = 12 ways.

Route 2 (Direct to C): Travel A to C directly (3 options). Combinations = 3 ways.

Since the traveler must choose either Route 1 or Route 2, add the independent possibilities together: Total ways = 12 + 3 = 15 ways.

When network pathways feature distinct "either/or" branching options, calculate the multiplicative permutations of each branch separately, then add the final branch totals together.

Answer: (c).

Question details

Year

2022

Paper

CSAT

Question

Q27

Section

Numerical Ability

Sub-topic

Permutations & Combinations

Type

Factual single

Difficulty

Easy

Source hint

Roads from A to B to C

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