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Q6·CSAT · Prelims 2023

Letters and envelopes derangement probability

NumericalPermutations & CombinationsNumber theoryHard

Question

There are four letters and four envelopes and exactly one letter is to be put in exactly one envelope with the correct address. If the letters are randomly inserted into the envelopes, then consider the following statements:

1It is possible that exactly one letter goes into an incorrect envelope.
2There are only six ways in which only two letters can go into the correct envelopes.

Which of the statements given above is/are correct?

Options

a

1 only

b

2 only

Answer
c

Both 1 and 2

d

Neither 1 nor 2

Explanation

Evaluate the probability/combinatorial statements independently:

Statement 1: If 3 letters match their correct envelopes perfectly, the 4th letter has only one envelope remaining—which must be its correct one. It is logically impossible for exactly one letter to be misplaced. Thus, Statement 1 is false.

Statement 2: We need exactly 2 letters in correct envelopes, meaning the remaining 2 letters must be completely deranged (misplaced). Step 1: Choose which 2 letters are correct: 4{2} = 4 × 3/2 = 6 ways. Step 2: Derange the remaining 2 letters. The number of ways to derange 2 items is exactly 1 (each goes into the other's envelope). Total ways = 6 × 1 = 6 ways. Statement 2 is correct.

In match/derangement puzzles, the number of ways to misplace exactly k items out of n is given by n{k} × D(n-k), where the derangement value D(2)=1.

Answer: (b).

Question details

Year

2023

Paper

CSAT

Question

Q6

Section

Numerical Ability

Sub-topic

Permutations & Combinations

Type

Number theory

Difficulty

Hard

Source hint

Number theory

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