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Q36·CSAT · Prelims 2023

Pigeonhole principle drawing balls from a box

ReasoningProbability & PigeonholeInequality logicHard

Question

A box contains 14 black balls, 20 blue balls, 26 green balls, 28 yellow balls, 38 red balls and 54 white balls. Consider the following statements:

1The smallest number n such that any n balls drawn from the box randomly must contain one full group of at least one colour is 175.
2The smallest number m such that any m balls drawn from the box randomly must contain at least one ball of each colour is 167.

Which of the above statements is/are correct?

Options

a

1 only

b

2 only

c

Both 1 and 2

Answer
d

Neither 1 nor 2

Explanation

Apply the Pigeonhole Principle to evaluate both worst-case scenario thresholds independently:

Statement 1 asks for a guaranteed full group of at least one color. To maximize the delay, assume we draw exactly 1 ball less than the full amount for every single color category available: Max incomplete draws = (14-1) + (20-1) + (26-1) + (28-1) + (38-1) + (54-1) = 13 + 19 + 25 + 27 + 37 + 53 = 174.

The very next ball drawn (174 + 1 = 175) must complete at least one of these color groups. Statement 1 is correct.

Statement 2 asks to guarantee at least one ball of each color. To maximize failure, assume we completely exhaust all the largest color groups first, leaving the single smallest group untouched: Max draws missing a color = 54 (white) + 38 (red) + 28 (yellow) + 26 (green) + 20 (blue) = 166.

The very next selection (166 + 1 = 167) is guaranteed to pull a ball from the remaining black group, ensuring all colors are represented. Statement 2 is correct.

To find the threshold for capturing at least one of each class, add all elements of all categories except the single smallest category, and then add 1.

Answer: (c).

Question details

Year

2023

Paper

CSAT

Question

Q36

Section

Logical & Analytical Reasoning

Sub-topic

Probability & Pigeonhole

Type

Inequality logic

Difficulty

Hard

Source hint

Logical deduction

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