Quantitative — Relative Speed & Sound Telemetry
Question
An explosion takes place at a certain distance from an army camp. As soon as the sensor in the camp receives the sound of the explosion, a drone starts flying towards the spot of explosion. The drone clicks a picture from the spot and the camp receives it at the same time. Immediately another drone starts flying to the spot and it also sends a picture as soon as it reaches the spot. The two pictures were received at 5:02 PM and 5:05 PM, respectively. If the speed of the drones is 30~m/s, at what time did the explosion take place? Assume that the speed of sound is 300~m/s.
Options
4:59:00 PM
4:59:02 PM
4:58:42 PM
4:56:32 PM
Explanation
Let d be the fixed distance between the military camp and the site of the explosion [cite: 3847, 3848].
T_1 = T₍explosion₎ + d/300 + d/30 = T₍explosion₎ + 11d/300 = 5:02 PM
t₍flight2₎ = d/30 = 3 minutes = 180 seconds \implies d = 180 × 30 = 5400 meters
Total delay from explosion to image 1 = 5400/300 + 5400/30 = 18s + 180s = 198 seconds 198 seconds = 3 minutes and 18 seconds
T₍explosion₎ = 5:02:00 PM - 3 min 18 s = 4:58:42 PM
Answer: (c).
Question details
Year
2026
Paper
CSAT
Question
Q21
Section
Quantitative Aptitude
Sub-topic
Time-Speed-Distance
Type
Arithmetic Problem
Difficulty
Hard
Source hint
Relative tracking — multi-agent sound and drone intervals
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