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Q19·CSAT · Prelims 2025

Tram overtaking two walkers - length

NumericalTime, Speed & DistanceTime-speed-distanceHard

Question

A tram overtakes 2 persons X and Y walking at an average speed of 3 km/hr and 4 km/hr in the same direction and completely passes them in 8 seconds and 9 seconds respectively. What is the length of the tram?

Options

a

15 m

b

18 m

c

20 m

Answer
d

24 m

Explanation

Let the tram's speed be v km/hr and its length be L meters. Convert pedestrian speeds to m/s: X = 3 × (5/18) m/s, Y = 4 × (5/18) m/s. The relative speed of the tram passing a person is (v - person's speed). Since L = Relative Speed × Time, we can equate the tram lengths for both cases: ⟨MATH⟩(v - 3) × 5/18 × 8 = (v - 4) × 5/18 × 9⟨/MATH⟩. Cancel 5/18 from both sides: 8v - 24 = 9v - 36 \implies v = 12 km/hr. Substitute v back to find L: L = (12 - 3) × 5/18 × 8 = 9 × 40/18 = 20 meters.

When calculating passing times in the same direction, always equate the distance (length of the vehicle) using the formula D = (S₍vehicle₎ - S₍pedestrian₎) × T.

Answer: (c).

Question details

Year

2025

Paper

CSAT

Question

Q19

Section

Numerical Ability

Sub-topic

Time, Speed & Distance

Type

Time-speed-distance

Difficulty

Hard

Source hint

Relative speed

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